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X=(0.5X^2)
We move all terms to the left:
X-((0.5X^2))=0
We calculate terms in parentheses: -((0.5X^2)), so:We get rid of parentheses
(0.5X^2)
We get rid of parentheses
0.5X^2
Back to the equation:
-(0.5X^2)
-0.5X^2+X=0
a = -0.5; b = 1; c = 0;
Δ = b2-4ac
Δ = 12-4·(-0.5)·0
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1}=1$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-1}{2*-0.5}=\frac{-2}{-1} =+2 $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+1}{2*-0.5}=\frac{0}{-1} =0 $
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